3 simple puzzles that puzzle the 9 out of 10! And you - will you find the answers?

Ready to test your wits? Let's see if you can solve three puzzles with a trick!

Riddle about a farmer and 15 chickens

  1. The farmer started his own business with 3 hens: they carried 3 eggs in 3 days. Having decided to expand the business, the farmer purchased 12 more birds. How many eggs will the farmer have after 15 days?

Riddle about the T-shirt

  1. Look carefully at the top. How many holes do you see on it?

Riddle of a gold bullion

  1. Rantier hired a builder to build a stone fence around the estate, promising to pay gold with him at the end of each working day. The builder must do the work in 7 days. The problem is that the rentier has only one bar of gold and saw - so old that it can only perform 2 cuts. How to handle the rentier, provided that he must give the builder a 1/7 part of the ingot daily?
The correct answers are waiting for you below.

  1. If you decide that the farmer will get 15 eggs - you hurried with conclusions. The hen carries an egg not once a day, but once every three days: this is the condition of the task. In total, from 15 hens per half a month the farmer will receive 75 eggs.
  2. In the condition, there is no indication of which holes are spoken. Therefore, the correct answer is 8: the neck, the bottom of the article, 2 sleeves and 2 holes - on the front and back :-)
  3. Rantier needs to saw the ingot twice, dividing it into bars in 1/7, 2/7 and 4/7 parts. On the first day he will give the builder 1/7 of the ingot, and in the second he will offer 2/7 and will take 1/7 as a surrender. On the third day he will return 1/7 part, and in the fourth he will give the largest block in 4/7 parts, taking 1/7 and 2/7. On the fifth day he will again pay 1/7 part of the ingot, in the sixth - he will give 2/7, returning to himself 1/7. On the seventh day, he will complete the transaction with the remaining one-seventh of the ingot, honestly following the condition.